r^2=1661.06

Solution for r^2=1661.06 equation:

r^2=1661.06

We move all terms to the left:

r^2-(1661.06)=0

We add all the numbers together, and all the variables

r^2-1661.06=0

a = 1; b = 0; c = -1661.06;
Δ = b2-4ac
Δ = 02-4·1·(-1661.06)
Δ = 6644.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6644.24}}{2*1}=\frac{0-\sqrt{6644.24}}{2}
=-\frac{\sqrt{}}{2}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6644.24}}{2*1}=\frac{0+\sqrt{6644.24}}{2}
=\frac{\sqrt{}}{2}
$